Ultimate Chemistry Spring Final Exam Study Guide 2025: Expert-Verified Questions, Detailed Answer Explanations & Proven Strategies for Top Grades and A+ Success

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Prepare for your 2025 Chemistry Spring Final Exam with this ultimate study guide. It offers expert-verified questions, detailed answers, and proven strategies for A+ success. Ideal for students aiming for top grades.
Achieve A+ success on your Chemistry Spring Final Exam with this ultimate 2025 study guide, designed for students aiming for top grades. Packed with expert-verified questions, detailed answer explanations, and proven strategies, this guide helps you master key chemistry concepts and excel with confidence. Perfect for high school or college students preparing for their spring finals.
  • Expert-Verified Questions: High-quality questions reviewed by chemistry professionals.
  • Detailed Answer Explanations: In-depth solutions to enhance your understanding.
  • Proven Strategies: Effective study and exam techniques for top performance.
  • Comprehensive Coverage: Includes all essential chemistry topics for the 2025 spring final.
  • Grade-Boosting Focus: Tailored to help students achieve A+ results.

Preview

1. The enthalpy of vaporization of methanol (CH₃OH) is 35.3 kJ/mol at the boiling point of
64.2°C. Calculate the entropy change for methanol going from a liquid to vapor. a) 600
J/K·mol
b) 551 J/K·mol
c) 105 J/K·mol
d) -105 J/K·mol
e) -551 J/K·mol
Correct Answer: c) 105 J/K·mol
Rationale: Entropy change is calculated using ΔS = ΔH / T (in Kelvin). Converting 64.2°C to Kelvin:
64.2 + 273.15 = 337.35 K.
ΔS = (35.3 kJ/mol) / (337.35 K) = 105 J/K·mol.
2. Which of the following represents an increase in entropy?
a) Freezing of water
b) Boiling of water
c) Crystallization of salt from a supersaturated solution
d) The reaction 2 NO(g) → N2O2(g)
e) The reaction 2 H2(g) + O2(g) → 2 H2O(g)
Correct Answer: b) Boiling of water
Rationale: Entropy (S) is a measure of disorder. When water boils, it changes from liquid to gas,
increasing molecular motion and disorder, which increases entropy.
3. Calculate the standard entropy change for the reaction:
Cu(s) + ½ O₂(g) → CuO(s)
Given:
• S°[Cu(s)] = 33.15 J/K·mol
• S°[O₂(g)] = 205.14 J/K·mol
• S°[CuO(s)] = 42.63 J/K·mol
a) 195.66 J/K
b) 93.09 J/K
c) -45.28 J/K
d) -93.09 J/K
e) 195.66 J/K
Correct Answer: d) -93.09 J/K Rationale:
ΔS° = Σ S°(products) – Σ S°(reactants) ΔS°
= [42.63] – [33.15 + 0.5(205.14)] ΔS° =
42.63 – 135.72 = -93.09 J/K.

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